Answer:
a) [tex]y + 3 = 2(x+2)[/tex] b) [tex]\sf y - 2 = -\frac{3}{8} ( x + 4)[/tex]
part A:
two points: [tex](-2,-3),(2,5)[/tex]
slope:
[tex]\sf \frac{y2-y1}{x2-x1}[/tex]
[tex]\sf \frac{5--3}{2--2}[/tex]
[tex]\sf \frac{4}{2}[/tex]
[tex]\sf 2[/tex]
equation:
[tex]\sf y - y1 = m ( x - x1 )[/tex]
[tex]\sf y - - 3 = 2 ( x - - 2)[/tex]
y + 3 = 2 (x+2)
part B:
two points: [tex](4,-1),(-4,2)[/tex]
slope:
[tex]\sf \frac{y2-y1}{x2-x1}[/tex]
[tex]\sf \frac{2--1}{-4-4}[/tex]
[tex]\sf -\frac{3}{8}[/tex]
equation:
[tex]\sf y - y1 = m ( x - x1 )[/tex]
[tex]\sf y - 2 = -\frac{3}{8} ( x - - 4)[/tex]
[tex]\sf y - 2 = -\frac{3}{8} ( x + 4)[/tex]
