Answer:
a) 49 oz and 59 oz
b) 81.8 %
c) 99.9 %
Step-by-step explanation:
[tex]X \sim N(54, 5^2)[/tex]
The Empirical Rule states that:
a)
[tex]\mu - \sigma=54-5=49[/tex]
[tex]\mu + \sigma=54+5=59[/tex]
⇒ 68% of the widget weights lie between 49 oz and 59 oz
b) 59 oz is 1 standard deviation from the mean
44 oz is 2 standard deviations from the mean
Therefore, 84.1 - 2.3 = 81.8 %
c) 39 is 3 standard deviations from the mean
Therefore, 100 - 0.1 = 99.9 %
**Please find attached a sketch of the distribution. The mean is shown with the solid line and the standard deviations with dash lines**