Answer:
Step-by-step explanation:
f and g are perpendicular
slope of g(x) = -1/3
Now,
[tex]g(x) =\dfrac{-1}{3}x+b[/tex]
f(x) and g(x) intersect at (2,14)
So, line defined by g(x) go through (2,14)
[tex]14=\dfrac{-1}{3}*2+b\\\\14=\dfrac{-2}{3}+b\\\\\\14+\dfrac{2}{3}=b\\\\\dfrac{14*3}{1*3}+\dfrac{2}{3}=b\\\\\\\dfrac{42}{3}+\dfrac{2}{3}=b\\\\\\b=\dfrac{44}{3}[/tex]
[tex]a +b =\dfrac{-1}{3}+\dfrac{44}{3}=\dfrac{43}{3}[/tex]
