Question

the equation of a function is y=2\3x +1\3 find
a] the value of y when'
i] x=-3 ii] x=1 1\2
b] the value of x when
i] y=1 ii] y=-1\6
please help me solve this equation asap i have 100 marks exam tommorow!

Answer 1

Answer:

a) i) y = - 5/3

  ii) y = 4/3

b) i) x = 1

   ii) x = -3/4

Step-by-step explanation:

$y=\dfrac23x +\dfrac13$

a) i) $x=-3$

$\implies y=\dfrac23(-3) +\dfrac13\\\\\\\implies y=\dfrac{-6}{3} +\dfrac13\\\\\\\implies y=\dfrac{1-6}{3} \\\\\\\implies y=-\dfrac53$

ii) $x=1\frac12=\dfrac32$

$\implies y=\dfrac23\left(\dfrac32\right) +\dfrac13\\\\\\\implies y=\dfrac{6}{6}+\dfrac13\\\\\\\implies y=\dfrac{3}{3}+\dfrac13\\\\\\\implies y=\dfrac{3+1}{3}\\\\\\\implies y=\dfrac43$

b) i) $y=1$

$\implies \dfrac23x +\dfrac13=1\\\\\\\implies \dfrac23x =1-\dfrac13\\\\\\\implies \dfrac23x =\dfrac23\\\\\\\implies x =1$

ii) $y=-\dfrac16$

$\implies \dfrac23x +\dfrac13=-\dfrac16\\\\\\\implies \dfrac23x =-\dfrac12\\\\\\\implies x =-\dfrac12 \div \dfrac23=-\dfrac12 \times\dfrac32=-\dfrac34$