Question

write a pythogorean triplet whose smallest number is 20?​

Answer 1

Answer:

20,21,29 or 20, 99 and 101.

Step-by-step explanation:

$a^{2} +b^{2} =c^{2}$

$20^{2} +21^{2} =29^{2}$

$400+441=841$

OR:

$a^{2} +b^{2} =c^{2}$

$20^{2} + 99^{2} = 101^{2}$

$400+9801=10201$