Question

use zero product property to solve.
0=6x^2-23+20

Answer 1

$\sf0=6x^2-23+20$

$\hookrightarrow\sf0=6x^2-3$

$\hookrightarrow\sf3=6x^2$

$\hookrightarrow\sf \dfrac{3}{6} =x^2$

$\hookrightarrow\sf\cancel \dfrac{3}{6} =x^2$

$\hookrightarrow\sf\dfrac{1}{2} =x^2$

$\hookrightarrow\sf x = \sqrt{ \dfrac{1}{2} }$