Answer:
r = [tex]\frac{12\pi }{\pi }[/tex] / 2 = 6
volume = 1/3 * π * r² * h
h = 3 * V/π * [tex]r^{2}[/tex]
h = [tex]\frac{3 * 264\pi }{\pi * 6^{2} }[/tex] = 22
The height of the right cone is 22 units.
'A right circular cone is a cone where the axis of the cone is the line meeting the vertex to the midpoint of the circular base.'
According to the given problem,
Radius of the right cone = [tex]\frac{\frac{12\pi }{\pi } }{2}[/tex]
= 6 units
Volume of the right cone = [tex]\frac{\pi r^{2}h }{3}[/tex]
Solving for h,
h = [tex]\frac{3*264\pi }{\pi *6^{2} }[/tex]
⇒ h = 22 units
Hence, we can conclude that the height of the right cone is 22 units.
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