Question

[Example 1]
Write an equation of the line passing through the
point (-3,10) that has a slope of5/3

Answer 1

Answer:

$y=\frac{5}{3}x+5$

Step-by-step explanation:

first, m (gradient) = 5/3, Point(-3,10) = (x1, y1)

substitute values into point-gradient formula:

$y-y_{1} =m(x-x_{1})\\y-(10)=\frac{5}{3}(x-(3))$

simplify...

$y-10=\frac{5}{3}x-5\\ y=\frac{5}{3}x+5$

Therefore

$y=\frac{5}{3}x+5$ is the answer