What is the surface area of this triangular prism rounded to the nearest tenth?

The surface area of the triangular prism, rounded to the nearest tenth is: 85.7 cm²
Surface area (SA) = bh + (s1 + s2 + s3)H
Given:
s1 = 6.8 cm
s2 = 5.1 cm
s3 = 8.5 cm
H = 2.5 cm
b = 6.8 cm
h = 5.1 cm
Plug in the values
Surface area of the triangular prism = 6.8 × 5.1 + (6.8 + 5.1 + 8.5)2.5
Surface area of the triangular prism = 85.7 cm²
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