Question

I have an unknown volume of gas at a pressure of 0. 50 atm and a temperature of 325 k. If i raise the pressure to 1. 2 atm, decrease the temperature to 320 k, and measure the final volume to be 48 liters, what was the initial volume of the gas?.

Answer 1

Answer:

117 liters

Explanation:

P1 = 0.50 atm, T1 = 325 K, V1 = ?

P2 = 1.2 atm, T2 = 320 K, V2 = 48 liters

Use P1*V1/T1 = P2*V2/T2

so V1 = V2 * (P2/P1) * (T1/T2) = 48 *(1.2/0.50) *(325/320) = 117 liters