Question

25 mL of 0.1 M lactic acid (CH, CH(OH)COOH) is titrated with 0.1 M sodium hydroxide (NaOH). The titration curve is shown. What is the approximate pKa? At the pKa, what fraction of the carboxyl group will have been converted to COO-? Express your answer as a decimal, not a percent. ​

Answer 1

The pKa and the fraction of the carboxyl group is mathematically given as

a)  pH= 3.2

b) 1/2 Carboxyl group will give  COO_

The carboxyl group and pKa

Question Parameters:

25 mL of 0.1 M lactic acid (CH, CH(OH)COOH) is titrated with 0.1 M sodium hydroxide (NaOH).

Generally the equation for the pH   is mathematically given as

ph = pka + log $\frac{[sodium lactate]}{[lactic acid]}$

Therefore

NaOH moles = 1/2 moles of acid then [sodium lactate]

Means

NaOH moles =[lactic acid]

Therefore

pH=pKa

Hence

Volume of NaOH = 12.5 ml

Therefore

pH = pka

pH= 3.2

b)

Generally at pKa =3.2, The 1/2 Carboxyl group will give  COO_

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