Question

how do you solve this problem ??

Answer 1

Answer:

$x=3c\sqrt{a} -b^2$

Step-by-step explanation:

$\sqrt{a} =\dfrac{x+b^2}{3c}$

Multiply both sides by 3c:

$\implies \sqrt{a} \cdot 3c=\dfrac{(x+b^2) \cdot 3c}{3c}$

$\implies 3c\sqrt{a} =x+b^2$

Subtract $b^2$ from both sides:

$\implies 3c\sqrt{a} -b^2=x+b^2-b^2$

$\implies 3c\sqrt{a}-b^2=x$

Switch sides:

$\implies x=3c\sqrt{a} -b^2$