Equal expressions can be taken as equal to some third quantity (which is not used previously, and is new). The equations for given equation to graph are: and
When you raise a number with an exponent, there comes a result.
Lets say you get
[tex]a^b = c[/tex]
Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows
[tex]b = \log_a(c)[/tex]
Log with base 10 is written as [tex]\log(x)[/tex] mostly.
For the given equation, using the above definition, we get:
[tex]log(x+1) = -x^2 + 10\\\\\\(x+1) = 10^{-x^2 + 10}\\x + 1 = 10^(-x^2} \times 10^10 = y\: \: \rm (say)\\[/tex]
Then we get two equations as:
[tex]y = x + 1\\y = 10^(-x^2} \times 10^10[/tex]
Graphing those equations and then getting their common intersection point will give us the solution, as plotted below in the attached graph.
Learn more about logarithms here:
https://brainly.com/question/20835449
Answer:
y1= -x^2 + 10
y2 = log (x + 1)
Step-by-step explanation:
These are the two equations that should be graphed.
