The Bernoulli counting process depicts that the value of X6 will be 0.
The value of X6 will be:
= N6 - N5
= 3 - 3
= 0
Also, the value of S3 will be:
X1 = 1 - 0 = 1
X2 = 1 - 1 = 0
X3 = 1 - 1 = 0
Therefore, S3 will be:
= X1 + X2 + X3
= 1 + 0 + 0
= 1
In conclusion, the value of S3 is 1.
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