Question

PLEASE HELP I WILL GIVE BRAINLIEST ITS URGENT!
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find:
The length of the angle bisector of angle A

Answer 1

i think the answer is 2.6 ‍♀️

Answer 2

Answer:

∠A is (5/3)√13

Step-by-step explanation:

The cosine of ∠A is $\frac{AC}{AB}$  = $\frac{5}{13}$

The cosine of half of ∠A is given by the half-angle formula:

cos(A/2) = √((1 +cos(A))/2) = √((1 + 5/13)/2) = √(9/13) = 3/√13

The length of the segment b is found from ...

cos(A/2) = 5/b   [adjacent side/hypotenuse]

 ∠ A = 5/cos(A/2) = 5/(3/√13)

∠ A = (5/3)√13

If Needed in decimal form : 6.01

[RevyBreeze]