Tom enlists the help of his friend John to move his car. They apply forces to the car as shown in the diagram. Here F1 - 449 N and F2 - 390 N and friction is negligible. In the diagram below, the mass
of the car = 3500 kg, 0, --25 and 0, - 12. (Assume the car faces the positive x-axis before the forces are applied.)
(1) Find the resultant force (in N) exerted on the car
magnitude
direction (counterclockwise from the +x-axis)
(6) What is the acceleration (in m/s) of the car?
magnitude
direction (counterclockwise from the +x-axis)
m/s?

The term resultant force refers to that force that has the same effect in magnitude and direction as two or more forces acting together. We can talk of the resultant force because force is a vector.

Since the image is not shown, let me assume that the two forces F1 nd F2 are in opposite directions. Hence; Fnet = 449 N - 390 N = 59 N

Now, the acceleration is obtained from; Fnet = ma

m = 3500 kg

a = Fnet/m = 59 N/3500 kg = 0.017 ms-2

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