a. The number of cubical packets on the floor is 30.
b. the number of cubical packets in 10 layers is 300 layers.
Since the volume of each cube is 1 cm³ and the volume of a cube V = L³ where L = length of side,
So, L = ∛V = ∛1 cm³ = 1 cm
So, the sides of the cubes are 1 cm long
Also, since the rectangular box is 5 cm long and 6 cm wide, to find the number of 1 cm³ cubical boxes that can be placed on the floor, we find the volume of that layer which is V = 5 cm × 6 cm × 1 cm = 30 cm³
The number of cubical packets on the floor is 30.
So, the number of cubical packets required, n = volume of layer/volume of cubical packet
= 30 cm³/1 cm³
= 30
The number of cubical packets on the floor is 30.
The number of cubical packets in 10 layers is 300 layers.
If there are 10 layers, then the number of packets on the layers, N = number of layer × number of packets/layer
= 10 × 30
= 300 layers.
So, the number of cubical packets in 10 layers is 300 layers.
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