Respuesta :

Topic : Linear equations in two variables.

Given :

  • 3x + 2y = -4 ––– (i)
  • x - 2y = 4 ––– (ii)

Solution :

Now,

(i) + (ii)

[tex] \qquad \sf \: { \dashrightarrow 3x + 2y + (x - 2y) = - 4 + 4}[/tex]

[tex] \qquad \sf \: { \dashrightarrow 3x + 2y + x - 2y = 0}[/tex]

[tex] \qquad \sf \: { \dashrightarrow 3x \: \cancel{ + 2y} + x \: \cancel{- 2y} = - 4 + 4}[/tex]

[tex] \qquad \sf \: { \dashrightarrow 4x = 0}[/tex]

[tex] \qquad \bf \: { \dashrightarrow x = 0}[/tex]

Now, substituting the value of x in Eq (i) :

[tex]\qquad \sf \: { \dashrightarrow 3x + 2y = -4}[/tex]

[tex]\qquad \sf \: { \dashrightarrow 3(0) + 2y = -4}[/tex]

[tex]\qquad \sf \: { \dashrightarrow 0 + 2y = -4}[/tex]

[tex]\qquad \sf \: { \dashrightarrow 2y = -4}[/tex]

[tex]\qquad \sf \: { \dashrightarrow y = \dfrac{ - 4}{2} }[/tex]

[tex]\qquad \bf \: { \dashrightarrow y = -2}[/tex]

Therefore, The value of x = 0 and y = -2

The solution to the two given simultaneous equations are; x = 0 and y = -2

How to find the solution to simultaneous equations?

We are given the simultaneous equations;

3x + 2y = -4   -----(eq 1)

x - 2y = 4      ------(eq 2)

Add eq1 and eq2 to get;

4x = 0

x = 0/4

x = 0

Substitute 0 for x in eq 2 to get;

0 - 2y = 4

-2y = 4

y = -4/2

y = -2

Read more about Simultaneous Equations at; https://brainly.com/question/16863577

ACCESS MORE