Sector Area Lvl 1: In circle F with m

Answer:
75.01 sq units
Step-by-step explanation:
Here,
[tex]\theta=m\angle EFG=86\degree[/tex]
[tex]r=EF=10\: units [/tex]
[tex]Area\: of \:sector= \frac{ \theta}{360 \degree} \times \pi \: {r}^{2} \\ \\ = \frac{ 86 \degree}{360 \degree} \times 3.14\: {(10)}^{2} \\ \\ = \frac{86 \times 314}{360} \\ \\ = 75.01 \: {units}^{2} [/tex]