Respuesta :

[tex] \bf \dag \gray{ \frak{Given:}}[/tex]

  • Length of rectangle = 4x + 8
  • Breadth of rectangle = 2x + 3

[tex] \\ \\ [/tex]

[tex] \bf \dag \gray{ \frak{To~Find:}}[/tex]

  • Perimeter of rectangle

[tex] \\ \\ [/tex]

We know:-

[tex] \bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2(length + breadth)}[/tex]

[tex] \\ \\ [/tex]

So:-

[tex]: \implies\sf Perimeter \: of \: rectangle = 2(length + breadth) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 2( \{4x + 8 \} + \{2x + 3 \}) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 2( 4x + 8 +2x + 3) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 2( 4x + 2x+ 8 + 3) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 2( 6x+ 8 + 3) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 2( 6x+11) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 2( 6x) + 2(11) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Perimeter \: of \: rectangle = 12x + 2(11) \\ [/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\bf Perimeter \: of \: rectangle = 12x + 22 \\ [/tex]

[tex] \\ \\ [/tex]

[tex]\therefore\underline {\textsf{\textbf{ Perimeter \: of \: rectangle = 12x + 22}}}[/tex]

The perimeter of the rectangle is 12x + 22.

How to solve the perimeter?

The perimeter of a rectangle is calculated by the formula:

= 2(length + Braeadth)

In this case, the perimeter will be:

= 2(4x + 8 + 2x + 3)

= 12x + 22

In conclusion, the perimeter is 12x + 22.

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