Graph the parabola.
Y = 4x^2 + 7
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Answer:
In Picture Below:
Step-by-step explanation:
To graph:
1. find the y intercept of the equation (y=4x^2+7, let x =0, y=4*0 +7 which equals y=7)
2. find the x intercepts (if there are any); y=4x^2+7, let y =0, 0=4x^2+7, 4x^2=-7, therefore no x intercepts (you cannot root a negative)
3. find vertex using -b/2a formula, a=4 b=0 c=7, therefore x =0, sub that into y=4x^2+7, y=7, therefore vertex is (0,7)
4. graph all this information