This question involves the concepts of density and mass.
The mass of water, displaced is "B. 20 g".
First, we will find out the volume of the woodblock by using the density of wood:
[tex]\rho_{wood} =\frac{m}{V}[/tex]
where,
Therefore,
[tex]1\ g/cm^3 = \frac{20\ g}{V}\\\\V=\frac{20\ g}{1\ g/cm^3}[/tex]
V = 20 cm³
Now, this is the same volume as the volume of water displaced by this block of wood. Hence, using the density of water, w can find the mass of water displaced:
[tex]\rho_{water}=\frac{m}{V}\\\\\rho_{water}(V)=m\\m= (1\ g/cm^3)(20\ cm^3)[/tex]
m = 20 g
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