Answer:
Step-by-step explanation:
Let find inverse of f(x):
f(x) = [tex]\frac{1}{x}[/tex] + 2
y = [tex]\frac{1}{x}[/tex] + 2
[tex]\frac{1}{x}[/tex] = y - 2
x = [tex]\frac{1}{y -2}[/tex]
y = [tex]\frac{1}{x -2}[/tex] is the inverse of f(x) = [tex]\frac{1}{x}[/tex] + 2
Therefore, f(x) and h(x) are not inverses.
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h(x) = [tex]\frac{4}{x-3}[/tex]
y = [tex]\frac{4}{x-3}[/tex]
x = [tex]\frac{4}{y-3}[/tex]
y - 3 = [tex]\frac{4}{x}[/tex]
y = [tex]\frac{4}{x}[/tex] + 3 is the inverse function of h(x)
