Question

Find the volume of the cone where Radius= 3 and height=7 .
Please use π = 22/7
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Answer 1

Answer:

Given -

♦ Radius of cone = 3 units

♦ Height = 7 units

$volume = \frac{1}{3} \pi \: r {}^{2} h \\ \\ = > \frac{1}{\cancel{3}} \times \frac{22}{\cancel{7} } \times \cancel{ 3} \times 3 \times \cancel{7} \\ \\ = > 22 \times 3 \\ \\ = > 66 \: units {}^{3}$

Go for it :D

Answer 2

Answer:

$\displaystyle \boxed{\tt \: VOLUME \; OF\; THE\; CONE = 66 \;units^3 }$

Step-by-step explanation:

Given:

Radius [r] = 3

Height [h] =7

To Find:

Volume of the cone

Solution:

We need to use the formula of volume of cone to find the volume of cone.

So We know that,

$\boxed{\rm \: Volume \: of \: the \: cone = \tt \cfrac{1}{3} \pi{r} {}^{2} h}$

Where,

• π = 22/7[According to the question]
• r = radius
• h = height

So put their values in the formulae:

• r = 3
• h = 7

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3 } \times \cfrac{22}{7} \times 3 {}^{2} \times 7$

Now Simplify to find the value of cone.

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3} \times \cfrac{22}{7} \times 3 \times 3 \times 7$

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3} \times \cfrac{22}{7} \times 9 \times 7$

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3} \times \cfrac{22}{7} \times 63$

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3} \times \cfrac{22}{ \cancel{7}{}^1} \times \cancel{63}\; \; {}^{9}$

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3} \times 22 \times 9$

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{3} \times 198$

$\rm \: Volume \: of \: the \: cone = \cfrac{1}{ \cancel{3} {}^{1} } \times \cancel{{ 198} } \: ^{66}$

$\rm \: Volume \: of \: the \: cone = 1 \times 66$

$\boxed{ \rm \: Volume \: of \: the \: cone = \boxed{\rm 66 \: \: units {}^{3}}}$

Hence, the volume of the cone would be 66 units^3 .

$\rule{225pt}{2pt}$

I hope this helps!