Answer:
x=2 and y=1
Step-by-step explanation:
2x+7y=11 eqn(1)
x+3y=5 eqn(2)×2
multiplying and subtracting eqn(2) ×2 from eqn(1)
2x+7y=11
-2x-6y=-10
y=1
putting the value of y=1 in eqn(1)
2x+7y=11
or,2x+7×1=11
or,2x+7=11
or,2x=11-7
or,x=4÷2
=x=2
From the given equation, we get the value of x = 2 and y = 1.
2x + 7y = 11 ...........(1)
x + 3y = 5 ............(2)
Multiplying (2) × -2, then we get
-2(x + 3y = 5) = -2x-6y = -10 ........(3)
multiplying and subtracting (2) × -2 from (1), then we get
[-2x-6y = -10] - [2x + 7y = 11]
then, we get y = 1
Substituting the value of y = 1 from (1), then we get
Fron (1), we get 2x + 7y = 11
put the value of y = 1
2x + 7×1 = 11
2x + 7 =11
2x = 11 - 7
x = 4 ÷ 2
x = 2
Therefore, the value of x = 2 and y = 1.
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