Question

How many g NaOH should be required to completely react 1.876 g of Copper (II) nitrate?

Molar mass of copper nitrate = 187.56 - Molar mass of NaOH = 40.0​

Answer 1

$\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2$

Moles of copper nitrate:-

$\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol$

• 1mol of Copper nitrate reacts with 2mol NaOH
• 0.001mol will react with 0.002mol NaOH

Madd of NaOH

$\\ \tt\hookrightarrow 0.002(40)=0.08g$