Respuesta :

[tex]\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2[/tex]

Moles of copper nitrate:-

[tex]\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol[/tex]

  • 1mol of Copper nitrate reacts with 2mol NaOH
  • 0.001mol will react with 0.002mol NaOH

Madd of NaOH

[tex]\\ \tt\hookrightarrow 0.002(40)=0.08g[/tex]

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