Answer:
48.075g(or 48g in correct sig figs)***
Explanation:
[tex]\frac{0.75mol}{1} *\frac{64.1g}{1 mol}[/tex]=48.075g
*64.1g is the mass of SO2 which is calculated by simply taking the mass of sulfur and oxygen(but doubling it since there are two oxygens) and adding them together(32.1+2x16.0)
**btw the mol units cancel because of dimensional analysis in case anyone was wondering why
***if your teacher is like mine and specifically wants your answer in correct sig figs, use the answer in parentheses as the original problem only has 2 sig figs
