A 50N crate is lifted 0.86m from the ground then is allowed to drop losing 15 J of energy. What is the new height of the crate?

We have that the new height of the crate is mathematically given as
Hn=0.56
Question Parameters:
A 50N crate is lifted 0.86m from the ground
then is allowed to drop losing 15 J of energy.
Generally the equation for the Potential energy is mathematically given as
P.E=mgh
Where
m=50/9.8
Therefore
h=15/(50/9.8*9.8)
h=0.3m
New height
0.86-0.3
Hn=0.56
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