Question

Mason is a beast on the basketball court. He has 15 games left. How many more games do you expect him to score 13-15 points

Answer 1

Using the binomial distribution, considering that he scores between 13 and 15 points in 60% of his games, he is expected to score 13-15 points in 9 games out of the remaining 15.

For each game, there are only two possible outcomes, either he scores between 13 and 15 points or he does not. His score on a single game is independent of any other game, hence the binomial distribution is used to solve this question.

What is the binomial probability distribution?

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected value of the binomial distribution is:

$E(X) = np$

In this problem:

• There are 15 games, hence n = 15.

• He scores between 13 and 15 points in 60% of his games, hence p = 0.6.

Then:

E(X) = np = 15 x 0.6 = 9.

He is expected to score 13-15 points in 9 games out of the remaining 15.

More can be learned about the binomial distribution at https://brainly.com/question/24863377