Respuesta :
1a. The amount spent using the truck is $128 ($4 x 160 x 4)/20.
1b. The amount spent using the car is $153.60 ($4 x 160 x 6)/25.
1c. It is more cost-efficient to use the truck; there is a savings of $25.60 ($153.60 - $128).
Data and Calculations:
Car's mileage per gallon = 25 miles
Truck's mileage per gallon = 20 miles
Distance to and from new house = 160 miles (80 x 2)
Number of loads with truck = 4
Number of loads with truck = 6
Cost of gas per gallon = $4
2. The amount that you save by commuting to work from the new house instead of the old is $1,200 ($4,000 - $2,800).
Data and Calculations:
Distance from the new house to workplace = 35 miles
Distance from the old house to workplace = 50 miles (35 + 15)
Cost of commuting to and from work from the new house per year = $2,800 (35 x 2 x $4 x 5 x 50)/25.
Cost of commuting to and from work from the old house per year = $4,000 (50 x 2 x $4 x 5 x 50)/25.
3. The hectares of land that it would take to supply one person's fuel use through present-day photosynthetic production is 0.02479 ha (0.0037 x 6.7).
Data and Calculations:
Units of fossil fuels burnt each year by an average American = 6.7 metric tons
Average net primary productivity = 0.0037 metric tons/ha/yr.
4. The percent of earth's land that one person would need to produce the equivalent of their yearly fossil fuel supply is 0%. (0.02479/15,000,000,000).
5. The percent of earth's land required for fuel production would be 1.322% (198.32/15,000).
Data and Calculations:
The total fuel production requirement of land = 198.32 million ha (0.02479 x 8,000,000,000).
6. The grams of sulfur released from the combustion of $100 of each source of coal are as follows:
Source A = 0.03 grams ($100/$0.60 x 0.018%)
Source B = 0.11 grams ($100/$1.40 x 0.153%)
Data and Calculations:
Rate of sulfur production from coal A = 0.018% (18/100,000)
Rate of sulfur production from coal B = 0.0153% (42/275,000)
Selling price of source A coal = $0.60 per kilogram
Selling price of source B coal = $1.40 per kilogram
7. Using Source A, the number of kilograms of sulfur released per year = 210,000 kilograms (7 billion x 0.03)/1,000.
8. Since there are 1,000 kWh in an MW, the number of homes the power plant can support is 500 homes (450 x 1,000)/900.
Data and Calculations:
Power plant's capacity = 500 MW
Capacitor factor = 0.9
Actual plant's production = 450 MW (500 x 0.9)
Power usage by a typical home = 900 kWh
9. The number of days to recover the $100 extra cost is 167 days ($100/$0.60).
Data and Calculations:
Cost Energy Star air conditioner unit = $300 per unit
Cost of standard unit = $200 per unit
To recover the extra $100 cost, you need to run the Energy
Cost savings of running Energy Star per day = $0.60 ($0.05 x 12)
10a. The cost of non-Energy Star model per year = $109.50 ($0.15/2 x 4 x 365).
10b. The amount saved on the electric bill over 5 years by buying the efficient Energy Star model over 5 years = $328.50 ($65.70 x 5).
Data and Calculations:
The cost of Energy Star model per year = $43.80 ($109.50 x 40%)
Savings per year using the Energy Star model per year = $65.70 ($109.50 - $43.80).
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