Question

Please help me, I’ll mark your answer as brainliest!

Answer 1

Answer:

(-oo, -1] U [10,oo)

Step-by-step explanation:

For the function,

$f(x) = \sqrt{x}$

The domain is All Reals Number greater than or equal to zero, but for this function

$f(x) = \sqrt{ {x}^{2} - 9x - 10 }$

WE Must factor to see what values will get

${x}^{2} - 9x - 10 = (x - 10)(x + 1)$

So know we Have

$\sqrt{(x - 10)(x + 1)}$

Set each equal to zero we have

$x = 10$

$x = - 1$

Now, we must find our interval.

If we plug in a negative number less than -1, we will get a positive interval so( -♾, -1] works. 0 doesn't work so we don't have a solution in between -1 and 10. Number greater than 10 work so We also have. [10,♾).

So our interval notation is