Question

Find the mean, median, mode, and range of the ages of employees in a firm, with calculations please. ​

Answer 1

Answer:

mean=23

median=23

mode=22 and 24

range=6

Step-by-step explanation:

$mean \: = \: \frac{sum \: of \: age \: \times \: frequency}{sum \: of \: frequency}$

$mean \: = \: \frac{(20 \times 5) + (22 \times 11) + (24 \times 11) + (26 \times 5)}{5 + 11 + 11 + 5} = 23$

$range \: = \: larger \: age \: - \: smaller \: age$

$range \: = \: 26 \: - \: 20 \: = \: 6$

mode = the most times an age appears = 22 and 24

median:

adding up the frequency: 5+11+11+4=31 (an odd number)

$median = ( \frac{n + 1}{2} ) {}^{th} = ( \frac{31 + 1}{2} ) {}^{th} = 16 {}^{th}$

to find the 16th position:

5 + 11 = 16, so the age at the 16th position is at age 22 and 24

$median \: = \: \frac{22 + 24}{2} = 23$