Question

4. Using stoichiometry, how many grams of sodium chloride should be produced from the reaction
if you started with 0.0119 moles of NaHCO3
Show Work:

Answer 1

NaHCO₃ (s) + HCl (aq) → NaCl (aq) + CO₂ (g) + H₂O (l)

From reaction coefficient: mole NaCl = mole NaHCO₃ = 0.0119

so mass NaCl:

= mol x Mr NaCl

= 0.0119 x 58.5 g/mol

= 0.696 g