burneremail13769736 burneremail13769736
  • 18-02-2022
  • Mathematics
contestada

What is the area of this triangle? (look at picture)

What is the area of this triangle look at picture class=

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ghaithgh
ghaithgh ghaithgh
  • 18-02-2022

Answer:

sin = opposite / hypotenuse

[tex] \sin(60) = \frac{x}{10} \\ \\ \frac{ \sqrt{3} }{2} = \frac{x}{10} \\ \\ 2x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{2} \\ \\ x = 5 \sqrt{3} [/tex]

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potatopeel
potatopeel potatopeel
  • 18-02-2022

Step-by-step explanation:

for x:

apply the sine rule. so

sinA/a = sinB/b

sin 90/10 = sin 60/ x

(cross multiply)

sin90 x = sin 60 × 10

x= (sin60×10)/sin90

x=8.66

Answer Link

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