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2 number has 6 sides 6 vertices and 9 diognals

The sides, vertices, and diagonals are parts of the polynomial that are

used to describe the polygon or are defined based on the polygon.

a. The sides are; TE, EM, MA, and AT

Vertices are; T, E, M, and A

The polygon has 2 distinct diagonals

b. The sides are; BN, NC, CA, AL, LU, and UB

Vertices are; B, N, C, A, L, and U

Number of distinct diagonals are 9

What are the sides vertices and diagonals of a polygon?

a. The sides of the quadrilateral TEMA are;

TE, EM, MA, and AT

The vertices of the quadrilateral are; T, E, M, and A

The number of distinct diagonals of a polygon are given as follows;

[tex]Number \ of \ diagonals = \mathbf{ \dfrac{n \cdot (n - 3)}{2}}[/tex]

Where;

n = The number of sides of the polygon

The number of distinct diagonals of the quadrilateral TEMA, with 4 sides is therefore;

[tex]Number \ of \ diagonals \ in \ the \ quadrilateral= \dfrac{4\times (4 - 3}{2} = 2[/tex]

The number of diagonals = 2

b. The sides of the hexagon BNCALU are;

BN, NC, CA, AL, LU, and UB

The vertices of the hexagon are; B, N, C, A, L, and U

[tex]Number \ of \ diagonals \ in \ the \ hexagon= \dfrac{6\times (6 - 3)}{2} = 9[/tex]

The number of distinct diagonals of the hexagon BNCALU = 9

Learn more about diagonals here;

https://brainly.com/question/4781816

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