Using simple interest, it is found that she would have to pay the loan back on May 17.
Simple interest is used when there is a single compounding per time period.
The amount of money after t years in is modeled by:
[tex]A(t) = A(0)(1 + rt)[/tex]
In which:
In this problem, the parameters are:
[tex]A(t) = 2317.97, A(0) = 2300, r = 0.0625[/tex]
Solving for t, we have that:
[tex]A(t) = A(0)(1 + rt)[/tex]
[tex]2317.97 = 2300(1 + 0.0625t)[/tex]
[tex]1 + 0.0625t = \frac{2317.97}{2300}[/tex]
[tex]1 + 0.0625t + 1.00781304348[/tex]
[tex]0.0625t = 0.00781304348[/tex]
[tex]t = \frac{0.00781304348}{0.0625}[/tex]
[tex]t = 0.125[/tex]
Considering a year has 365 days:
0.125 x 365 = 46
46 days after April 1, hence she would have to pay it back on May 17.
More can be learned about simple interest at https://brainly.com/question/25296782