Question

What is the sum of a geometric series of 12 terms that begins with 10 and has a common ratio of 2?

Answer 1

Answer:

$40950$

Step-by-step explanation:

$S_n=\frac{a_1(1-r^n)}{1-r}\\\\S_{12}=\frac{10(1-(2)^{12})}{1-2}\\\\S_{12}=\frac{10(1-4096)}{-1}\\\\S_{12}=\frac{10(-4095)}{-1}\\\\S_{12}=10(4095)\\\\S_{12}=40950$