The volume in milliliters of 0.0180 M Ba(OH)₂ that is required to neutralize 55.0 mL of 0.0500 M HCl is 152.78mL.
HOW TO CALCULATE VOLUME?
The volume of a solution can be calculated by using the following expression:
C1V1 = C2V2
Where;
- C1 = initial concentration
- C2 = final concentration
- V1 = initial volume
- V2 = final volume
The volume can be calculated as follows;
0.0180 × V1 = 55 × 0.05
0.0180V1 = 2.75
V1 = 2.75 ÷ 0.0180
V1 = 152.78mL
Therefore, the volume in milliliters of 0.0180 M Ba(OH)₂ that is required to neutralize 55.0 mL of 0.0500 M HCl is 152.78mL.
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