Question

What is the axis of symmetry in the function f(x)=(x-1)^2+2

Answer 1

Answer:

x = 1

Step-by-step explanation:

• Vertex form of a quadratic equation:  $f(x)=a(x-h)^2+k$
  where $(h, k)$ is the vertex

• The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

The vertex of  $f(x)=(x-1)^2+2$ is (1, 2)

Therefore, the x-coordinate is 1, so x = 1 is the equation of the axis of symmetry.