The weekly revenue for a company is r=-4p^2+40p+887, where p is the price of the company’s product. Use the discriminant to find whether there is a price for which the weekly revenue would be $1200

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Answer:

No, there is no price for which the weekly revenue would be 1200

Step-by-step explanation:

If r = 1200

[tex]-4p^2+40p+887=1200\\\\\implies -4p^2+40p-313=0[/tex]

Therefore, [tex]a=-4, \ \ \ b=40, \ \ \ c=-313[/tex]

discriminant = [tex]b^2-4ac[/tex]

[tex]\implies 40^2-4(-4)(-313) = 1600 - 5008=-3408\\\\-3408<0 \implies \textsf{no real solutions}[/tex]

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