What is the equation of the line shown on the coordinate plane below
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Answer:
Step-by-step explanation:
We need to find the slope(m)
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{2}[/tex]
y = mx + b
y = [tex]\frac{3}{2}[/tex]x + b
(0,3)
y = [tex]\frac{3}{2}[/tex]x + b
3 = [tex]\frac{3}{2}[/tex](0) + b
3 = b
y = [tex]\frac{3}{2}[/tex]x + 3
I attached the graph to check the answer :)
Hope this helps!