Question

Find the equation for the line that passes through the point (4, -2), and that is parallel to the line with the equation y = 1/3x-8/3

Answer 1

Answer:

$y=\frac{1}{3}x-\frac{10}{3}$

Step-by-step explanation:

Parallel lines have the same slope, but different y-intercepts, thus:

$y=\frac{1}{3}x+b\\\\-2=\frac{1}{3}(4)+b\\ \\-2=\frac{4}{3}+b\\ \\-\frac{10}{3}=b$

This means our parallel equation that passes through (4,-2) is $y=\frac{1}{3}x-\frac{10}{3}$.