Question

The ability to taste PTC is due to a single dominant allele "T." You sampled 215 individuals and determined
that 150 could detect the bitter taste of PTC and 65 could not. Calculate the following frequencies.
A. The frequency of the recessive allele,
B. The frequency of the dominant allele.
C. The frequency of the heterozygous individuals.
Please show all work

Answer 1

The frequency of the recessive allele would be 0.55, that of the dominant allele would be 0.45, and that of the heterozygous individuals would be 0.495

Population genetics

Recall that for a population in Hardy-Weinberg equilibrium:

p2 + 2pq + q2 = 1

Also, p + q = 1

Where:

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p2 = percentage of homzygous dominant individuals

q2 = percentage of homzygous recessive individuals

2pq = percentage of heterozygous individuals

In this case, the percentage of homzygous recessive individuals can be calculated as:

Homzygous recessive = those that could not taste PTC = 65/215

q2 = 65/215 = 0.302

    q = 0.55

Since p + q = 1

           p = 1 - 0.55

                   = 0.45

The frequency of the heterozygous individuals = 2pq

                      = 2 x 0.45 x 0.55

                        = 0.495

More on Hardy-Weinberg equilibrium can be found here: https://brainly.com/question/3406634