Question

The first two of three consecutive multiples of 9 sum to 2511. What are the numbers?

Answer 1

Answer:

First = 1251

Second = 1260

Third = 1268

Step-by-step explanation:

First: 9x

Second: 9(x+1)

Third: 9(x+2)

${ \tt{first + second = 2511}} \\ { \tt{9x + 9(x + 1) = 2511}} \\ { \tt{9x + 9x + 9 = 2511}} \\ { \tt{18x = 2502}} \\ { \tt{x = 139}}$

First = 9 × 139 = 1251

First = 9 × 139 = 1251Second = 9(139 + 1) = 1260

First = 9 × 139 = 1251Second = 9(139 + 1) = 1260Third = 9(139 + 2) = 1268