Question

2/3(9a+18b)=6a+kb
Which value of k makes the equation true?


1.) 9

2.) 3

4.) 12

5.) 6

Answer 1

Answer:

4.) 12

Step-by-step explanation:

$\frac{2}{3} (9a + 18b) = 6a + kb \\ \\ \implies \: \frac{2}{3} \times 9a + \frac{2}{3} \times 18b = 6a + kb \\ \\ \implies \: { 6a} + 12b = 6a + kb \\ \\ \implies \: \cancel{ 6a} + 12b - \cancel{ 6a} = kb \\ \\ \implies \: 12b = kb \\ \\ \implies \: k = \frac{12\cancel b}{\cancel b} \\ \\ \huge \implies \: k = 12$