Question

Write a sine function that has a midline of 5, an amplitude of 4 and a period of 7/5

Answer 1

Answer:

$y=4sin(\frac{10\pi}{7}x)+5$

Step-by-step explanation:

Recall formula

$y=asin(bx+c)+d\\\\y=4sin(bx)+5$

Determine b from period

$\frac{2\pi}{b}=\frac{7}{5}\\ \\ 10\pi=7b\\\\b=\frac{10\pi}{7}$

Final Equation

$y=4sin(\frac{10\pi}{7}x)+5$