Question

5 F2 (g) + 2 NH3 (g) -> N2F4 (g) + 6 HF (g)

If you reacted 4.3 miles of F2 how many moles of HF would be produced?

Answer 1

Answer:5 F2 (g) + 2 NH3 (g) -> N2F4 (g) + 6 HF (g)

Explanation:moles = mass/molar mass

mass =molar mass x mole

a) moles of Nh3 = 58.5/17 = 3.44 moles

the mole ratio of F2:NH3 = 5:2

the moles of F2 =3.44x5/2=8.6 moles

mass= 8.6 x 38 = 326.8 grams of F2

B) moles of Hf = 3.89/20 = 0.1945 moles

mole ratio NH3:Hf= 2:6

moles of NH3 = 0.1945 x2/6 = 0.0648 moles

mass =0.0648 x17 = 1.102 grams of NH3

C) moles of f2 = 217/38 =5.711 moles

mole ratio N2F6:F2 =5:1

moles of N2F4=5.711 x1/5=1.142 moles

mass = 1.142 x104 = 118.77 grams of N2F4