Answer:
x=4+5yif sum is increased by 3 (x+y+3), result is 31x+y+3=31minus 3 both sidesx+y=28x=4+5y subsiutute4+5y+y=284+6y=28minus 4 both sides6y=24divide by 6y=4sub backx=4+5yx=4+5(4)x=4+20x=24the numbers are 24 and 4
Step-by-step explanation:
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Answer:
29 and 5
Step-by-step explanation:
Given system of equations
[tex]\left \{ {{x=4+5y} \atop {x+y+1=35}} \right.[/tex]
Substitute top equation into bottom equation to determine y
[tex]x+y+1=35\\\\(4+5y)+y+1=35\\\\4+5y+y+1=35\\\\5+6y=35\\\\6y=30\\\\y=5[/tex]
Substitute y=5 into top equation to determine the x-value
[tex]x=4+5y\\\\x=4+5(5)\\\\x=4+25\\\\x=29[/tex]
Therefore, the two numbers are 29 and 5
