Question

Please help me find Sin(g)

Answer 1

Answer:

$sin(G)=\frac{21}{35}$

Step-by-step explanation:

Solve for line segment CA:

$a^2+b^2=c^2\\\\14^2+(CA)^2=17.5^2\\\\196+(CA)^2=306.25\\\\(CA)^2=110.25\\\\CA=10.5$

Determine sin(G) which is similar to sin(T)

$sin(G)=\frac{opposite}{hypotenuse}\\ \\sin(G)=\frac{10.5}{17.5}\\ \\G=sin^{-1}(\frac{10.5}{17.5})\\ \\G\approx36.87^\circ$

Therefore, $sin(G)=\frac{10.5}{17.5}=\frac{21}{35}$ where $m\angle G=36.87^\circ$