The given sequence the recursive function will be [tex]a_n = 4a_{n-1}[/tex]
The iterative rule for the sequence is [tex]T_n = 8(4)^{n-1[/tex]
Given the sequence of numbers 8, 32, 128, 512, …
From the given sequence the recursive function will be [tex]a_n = 4a_{n-1}[/tex]
For the iterative sequence, we will use the common ratio and the first term as shown;
[tex]T_n=ar^{n-1}\\T_n=8(4)^{n-1}[/tex]
Hence the iterative rule for the sequence is [tex]T_n = 8(4)^{n-1[/tex]
Learn more on sequence here: https://brainly.com/question/7882626